(t-6)/(t^2-3t)=(-6)/(t^2-9)

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Solution for (t-6)/(t^2-3t)=(-6)/(t^2-9) equation:


D( t )

t^2-(3*t) = 0

t^2-9 = 0

t^2-(3*t) = 0

t^2-(3*t) = 0

t^2-3*t = 0

t^2-3*t = 0

DELTA = (-3)^2-(0*1*4)

DELTA = 9

DELTA > 0

t = (9^(1/2)+3)/(1*2) or t = (3-9^(1/2))/(1*2)

t = 3 or t = 0

t^2-9 = 0

t^2-9 = 0

1*t^2 = 9 // : 1

t^2 = 9

t^2 = 9 // ^ 1/2

abs(t) = 3

t = 3 or t = -3

t in (-oo:-3) U (-3:0) U (0:3) U (3:+oo)

(t-6)/(t^2-(3*t)) = -6/(t^2-9) // + -6/(t^2-9)

(t-6)/(t^2-(3*t))-(-6/(t^2-9)) = 0

(t-6)/(t^2-3*t)+6*(t^2-9)^-1 = 0

(t-6)/(t^2-3*t)+6/(t^2-9) = 0

t^2-3*t = 0

t^2-3*t = 0

t*(t-3) = 0

t-3 = 0 // + 3

t = 3

t*(t-3) = 0

(t-6)/(t*(t-3))+6/(t^2-9) = 0

((t-6)*(t^2-9))/(t*(t-3)*(t^2-9))+(6*t*(t-3))/(t*(t-3)*(t^2-9)) = 0

(t-6)*(t^2-9)+6*t*(t-3) = 0

t^3-27*t+54 = 0

t^3-27*t+54 = 0

t^3-27*t+54 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6, 9, -9, 18, -18, 27, -27, 54, -54 }

1

t = 1

t^3-27*t+54 = 28

1

-1

t = -1

t^3-27*t+54 = 80

-1

2

t = 2

t^3-27*t+54 = 8

2

-2

t = -2

t^3-27*t+54 = 100

-2

3

t = 3

t^3-27*t+54 = 0

3

t-3

t^2+3*t-18

t^3-27*t+54

t-3

3*t^2-t^3

3*t^2-27*t+54

9*t-3*t^2

54-18*t

18*t-54

0

t^2+3*t-18 = 0

DELTA = 3^2-(-18*1*4)

DELTA = 81

DELTA > 0

t = (81^(1/2)-3)/(1*2) or t = (-81^(1/2)-3)/(1*2)

t = 3 or t = -6

t in { -6, 3, 3}

(t+6)*(t-3)^2 = 0

((t+6)*(t-3)^2)/(t*(t-3)*(t^2-9)) = 0

((t+6)*(t-3)^2)/(t*(t-3)*(t^2-9)) = 0 // * t*(t-3)*(t^2-9)

(t+6)*(t-3)^2 = 0

( t+6 )

t+6 = 0 // - 6

t = -6

( t-3 )

t-3 = 0 // + 3

t = 3

t in { 3}

t = -6

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